, as shown
below, the central angle
is
twice the angle
.

To prove this, we use the fact that
is a right angle
and the fact that the angles in any triangle sum to
.

Summing the angles in triangle BDC, we get
, or
.
Since triangle ADB is isosceles (two of its legs are
radii of the circle), the missing angle must
be equal to
.
[Return to geometry review] | [Return to Archimedes's method]
Neal Carothers - carother@bgnet.bgsu.edu